x^2+36x+76=0

Solution for x^2+36x+76=0 equation:

x^2+36x+76=0

a = 1; b = 36; c = +76;
Δ = b2-4ac
Δ = 362-4·1·76
Δ = 992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{992}=\sqrt{16*62}=\sqrt{16}*\sqrt{62}=4\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{62}}{2*1}=\frac{-36-4\sqrt{62}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{62}}{2*1}=\frac{-36+4\sqrt{62}}{2}
$